Բ뾶RR>2
СԲֱɹɶ뾶\(\sqrt{R^2-4}/2\)\(S_1=(R^2/4-1)\pi\)
ɴˣ=\((1+{3R^2 \over 4})\pi\)
СԲֱɹɶ뾶\(\sqrt{R^2-4}/2\)\(S_1=(R^2/4-1)\pi\)
ɴˣ=\((1+{3R^2 \over 4})\pi\)
���༭ʱ��: 2021-09-01 11:41:33
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