a/y=x,
b/y=1/tan (2α)=(1-x^2)/(2x)
解之，y^2=a*a+2ab.
b/y=1/tan (2α)=(1-x^2)/(2x)
解之，y^2=a*a+2ab.
所跟帖: 脝陆脮媒 : 碌脷脪禄脤芒陆芒路篓戮芦虏脢拢禄碌脷露镁脤芒 2023-06-06 19:22:30
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