СԲ뾶Ϊ\(r_1, r_2\)
ԲСԲ
=\((r_1+r_2)^2\pi -r_1^2\pi -r_2^2\pi=2r_1r_2\pi\)
Ϊһ롣
ԲСԲ
=\((r_1+r_2)^2\pi -r_1^2\pi -r_2^2\pi=2r_1r_2\pi\)
Ϊһ롣
所跟帖: ƽÕý : ÓÖÀ´ÊýѧÌ⣺ 2023-03-16 18:40:16
1£º4¦Ð2023-03-16 19:17:20 [点击:1498]
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