\(\cot \frac{A}{2}=\frac{1+\cos A}{\sin A}=\frac{b+c}{a}\)
cosB/2)ҲƳ뼴ɡ
ãǰķȽstraightforward
֪=>ǿɵ => ҳϵз̡
cosB/2)ҲƳ뼴ɡ
ãǰķȽstraightforward
֪=>ǿɵ => ҳϵз̡
所跟帖: ·®¹ : µÚÒ»ÌâÓиöºÜƯÁÁµÄ½â 2023-04-14 02:05:30
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